Difference between revisions of "1953 AHSME Problems/Problem 15"
(Created page with "==Problem 15== A circular piece of metal of maximum size is cut out of a square piece and then a square piece of maximum size is cut out of the circular piece. The total amoun...") |
Shurong.ge (talk | contribs) (→Solution) |
||
Line 6: | Line 6: | ||
==Solution== | ==Solution== | ||
− | The maximum diameter of the circular piece is the same as the side length of the square piece, so the circle is tangent to the square on all four sides. The maximum size a square piece that you can cut from the circle now has 4 edges that are the same as the square created by connecting the four midpoints of the original square. If the side length of the original square is <math>s</math>, then the sides of the final square have length <math>\sqrt{\frac{s^2}{2}}</math>, so its area is <math>\frac{s^2}{2}</math>, <math>\frac{1}{2}</math> the area of the original square. | + | The maximum diameter of the circular piece is the same as the side length of the square piece, so the circle is tangent to the square on all four sides. The maximum size a square piece that you can cut from the circle now has 4 edges that are the same as the square created by connecting the four midpoints of the original square. If the side length of the original square is <math>s</math>, then the sides of the final square have length <math>\sqrt{\frac{s^2}{2}}</math>, so its area is <math>\frac{s^2}{2}</math>, <math>\frac{1}{2}</math> the area of the original square. |
+ | <math>\textbf{(B)}</math> | ||
==See Also== | ==See Also== |
Latest revision as of 14:41, 27 January 2020
Problem 15
A circular piece of metal of maximum size is cut out of a square piece and then a square piece of maximum size is cut out of the circular piece. The total amount of metal wasted is:
Solution
The maximum diameter of the circular piece is the same as the side length of the square piece, so the circle is tangent to the square on all four sides. The maximum size a square piece that you can cut from the circle now has 4 edges that are the same as the square created by connecting the four midpoints of the original square. If the side length of the original square is , then the sides of the final square have length , so its area is , the area of the original square.
See Also
1953 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 14 |
Followed by Problem 16 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.