Difference between revisions of "1953 AHSME Problems/Problem 19"

(Created page with "==Problem 19== In the expression <math>xy^2</math>, the values of <math>x</math> and <math>y</math> are each decreased <math>25</math> %; the value of the expression is: <m...")
 
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<math>xy^2</math>
 
<math>xy^2</math>
  
<math>(\frac{3x}{4})(\frac{3y}{4})^2</math>
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<math>(\frac{3}{4}x)(\frac{3}{4}y)^2</math>
  
 
<math>(\frac{3}{4})^3xy^2</math>
 
<math>(\frac{3}{4})^3xy^2</math>
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<math>xy^2-\frac{27}{64}xy^2 = \frac{37}{64}xy^2 \implies \textbf{(C)}</math>
 
<math>xy^2-\frac{27}{64}xy^2 = \frac{37}{64}xy^2 \implies \textbf{(C)}</math>
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==See Also==
 
==See Also==
  

Latest revision as of 21:48, 1 April 2017

Problem 19

In the expression $xy^2$, the values of $x$ and $y$ are each decreased $25$ %; the value of the expression is:

$\textbf{(A)}\ \text{decreased } 50\% \qquad \textbf{(B)}\ \text{decreased }75\%\\  \textbf{(C)}\ \text{decreased }\frac{37}{64}\text{ of its value}\qquad \textbf{(D)}\ \text{decreased }\frac{27}{64}\text{ of its value}\\ \textbf{(E)}\ \text{none of these}$

Solution

$xy^2$

$(\frac{3}{4}x)(\frac{3}{4}y)^2$

$(\frac{3}{4})^3xy^2$

$\frac{27}{64}xy^2$

$xy^2-\frac{27}{64}xy^2 = \frac{37}{64}xy^2 \implies \textbf{(C)}$

See Also

1953 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 18
Followed by
Problem 20
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