Difference between revisions of "1953 AHSME Problems/Problem 30"
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==Solution== | ==Solution== | ||
| − | When Mr.A sells the house at a <math>10</math>% loss, he sells it for <math>9000(1 - .1) = 8100</math>. When Mr.B sells the house back to Mr. A at a <math>10</math> % gain he sells it for <math>8100(1 + .1) = 8910</math>. Therefore Mr. A has lost <math>8100-8910 = | + | When Mr.A sells the house at a <math>10</math>% loss, he sells it for <math>9000(1 - .1) = 8100</math>. When Mr.B sells the house back to Mr. A at a <math>10</math> % gain he sells it for <math>8100(1 + .1) = 8910</math>. Therefore Mr. A has lost <math>8100-8910 = 810</math> dollars, so the answer is <math>\boxed{D}</math>. |
==See Also== | ==See Also== | ||
Latest revision as of 17:33, 22 April 2020
Problem 30
A house worth $ 
is sold by Mr. A to Mr. B at a 
% loss. Mr. B sells the house back to Mr. A at a % gain.
The result of the two transactions is:
Solution
When Mr.A sells the house at a % loss, he sells it for 
. When Mr.B sells the house back to Mr. A at a % gain he sells it for 
. Therefore Mr. A has lost 
dollars, so the answer is 
.
See Also
| 1953 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 29 |
Followed by Problem 31 | |
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| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
