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Difference between revisions of "1953 AHSME Problems/Problem 42"

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==Problem==
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The centers of two circles are <math>41</math> inches apart. The smaller circle has a radius of <math>4</math> inches and the larger one has a radius of <math>5</math> inches.
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The length of the common internal tangent is:
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<math>\textbf{(A)}\ 41\text{ inches} \qquad
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\textbf{(B)}\ 39\text{ inches} \qquad
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\textbf{(C)}\ 39.8\text{ inches} \qquad
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\textbf{(D)}\ 40.1\text{ inches}\\ \textbf{(E)}\ 40\text{ inches} </math>
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==Solution==

Revision as of 01:47, 4 February 2020

Problem

The centers of two circles are $41$ inches apart. The smaller circle has a radius of $4$ inches and the larger one has a radius of $5$ inches. The length of the common internal tangent is:

$\textbf{(A)}\ 41\text{ inches} \qquad \textbf{(B)}\ 39\text{ inches} \qquad \textbf{(C)}\ 39.8\text{ inches} \qquad \textbf{(D)}\ 40.1\text{ inches}\\ \textbf{(E)}\ 40\text{ inches}$

Solution

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