Difference between revisions of "1953 AHSME Problems/Problem 42"

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{{AHSME 50p box|year=1953|num-b=41|num-a=43}}
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{{MAA Notice}}

Revision as of 01:48, 4 February 2020

Problem

The centers of two circles are $41$ inches apart. The smaller circle has a radius of $4$ inches and the larger one has a radius of $5$ inches. The length of the common internal tangent is:

$\textbf{(A)}\ 41\text{ inches} \qquad \textbf{(B)}\ 39\text{ inches} \qquad \textbf{(C)}\ 39.8\text{ inches} \qquad \textbf{(D)}\ 40.1\text{ inches}\\ \textbf{(E)}\ 40\text{ inches}$

Solution

See Also

1953 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 41
Followed by
Problem 43
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All AHSME Problems and Solutions


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