1953 AHSME Problems/Problem 6

Problem 6

Charles has $5q + 1$ quarters and Richard has $q + 5$ quarters. The difference in their money in dimes is:

$\textbf{(A)}\ 10(q - 1) \qquad \textbf{(B)}\ \frac {2}{5}(4q - 4) \qquad \textbf{(C)}\ \frac {2}{5}(q - 1) \\ \textbf{(D)}\ \frac{5}{2}(q-1)\qquad \textbf{(E)}\ \text{none of these}$

Solution

$5q+1-q-5\implies 4p-4\implies\frac{4(p-1)}{10}\implies\frac{2(p-1)}{5}$ , $\fbox{D}$

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1953 AHSME Problems/Problem 6

Problem 6

Solution