Difference between revisions of "1954 AHSME Problems/Problem 1"
Katzrockso (talk | contribs) (Created page with "== Problem 1== The square of <math>5-\sqrt{y^2-25}</math> is: <math>\textbf{(A)}\ y^2-5\sqrt{y^2-25} \qquad \textbf{(B)}\ -y^2 \qquad \textbf{(C)}\ y^2 \\ \textbf{(D)}\ (5-...") |
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== Solution == | == Solution == | ||
| − | <math>(5-\sqrt{y^2-25})^2 | + | <math>(5-\sqrt{y^2-25})^2 = 5^2-2\cdot 5\cdot\sqrt{y^2-25}+y^2-25 = y^2-10\sqrt{y^2-25}</math> <math>\ \Rightarrow</math> <math>\fbox{E}</math> |
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| + | ==See Also== | ||
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| + | {{AHSME 50p box|year=1954|before=First Problem|num-a=2}} | ||
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| + | {{MAA Notice}} | ||
Latest revision as of 20:33, 17 February 2020
Problem 1
The square of 
is:
Solution
See Also
| 1954 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
