Difference between revisions of "1954 AHSME Problems/Problem 13"

Revision as of 14:26, 6 June 2016

A quadrilateral is inscribed in a circle. If angles are inscribed in the four arcs cut off by the sides of the quadrilateral, their sum will be:

$\textbf{(A)}\ 180^\circ \qquad \textbf{(B)}\ 540^\circ \qquad \textbf{(C)}\ 360^\circ \qquad \textbf{(D)}\ 450^\circ\qquad\textbf{(E)}\ 1080^\circ$

?

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	== Solution ==		== Solution ==
−	~~<math>180(4-2)=360, \fbox{C}</math>~~	+	?