# Difference between revisions of "1955 AHSME Problems/Problem 37"

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<cmath> \text{5 9 4}</cmath> | <cmath> \text{5 9 4}</cmath> | ||

Out difference is <math>594</math>. Therefore, the next two digits, from right to left, are <math>\boxed{\textbf{(B) } \text{9 and 5}}</math>. | Out difference is <math>594</math>. Therefore, the next two digits, from right to left, are <math>\boxed{\textbf{(B) } \text{9 and 5}}</math>. | ||

+ | |||

==See Also== | ==See Also== | ||

Go to the rest of the [[1955 AHSME Problems]] | Go to the rest of the [[1955 AHSME Problems]] | ||

{{MAA Notice}} | {{MAA Notice}} |

## Latest revision as of 14:34, 24 November 2020

A three-digit number has, from left to right, the digits , and , with . When the number with the digits reversed is subtracted from the original number, the units' digit in the difference is 4. The next two digits, from right to left, are:

## Solution

We can set up the subtraction like this: Since , we need to borrow the one from the tens column. Since the result of the tens column is 0, the taken 1 would result in the tens digit being 9:

We can assign a value for and , since that doesn't impact the difference, so lets say that and . Since , we can subtract one from the hundred's digit: Out difference is . Therefore, the next two digits, from right to left, are .

## See Also

Go to the rest of the 1955 AHSME Problems

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.