Difference between revisions of "1956 AHSME Problems/Problem 35"

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First, we create a circle and its <math>2</math> radii. Both of these have length <math>16</math>. When we join them, we get our first chord. Let's call this <math>AB</math>. Now, we can create two more chords of our own choice, as long as both of them start from points <math>A</math> and <math>B</math> respectively and our final figure looks like a rhombus. Let's call these newly created points <math>C</math> and <math>D</math>. Thus, now we have our rhombus <math>ABCD</math>. Since we known the formula for a rhombus's area is <math>A = \frac{pq}{2}</math>, we can now successfully substitute the <math>p</math> and the <math>q</math> both with <math>16 feet</math> (since, in our case, we had a circle, both our <math>p</math> and <math>q</math> are going to be the same). After substituting, we get: <math>\frac{16*16}{2}</math>; upon using arithmetic, we yield our answer to be <math>128 feet^2</math>.
-Solution by '''DRAGONWARRIOR123'''

Latest revision as of 19:09, 11 February 2020

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