Difference between revisions of "1956 AHSME Problems/Problem 43"

(Created page with "== Problem 43== The number of scalene triangles having all sides of integral lengths, and perimeter less than <math>13</math> is: <math>\textbf{(A)}\ 1 \qquad\textbf{(B)}\...")
 
 
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==Solution==
 
==Solution==
We can write all possible triangles starting with a minimum side length of <math>1.</math>
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We can write all possible triangles adding up to 12 or less
<cmath>(1, 6, 6)</cmath>
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<cmath>(2, 4, 5)=11</cmath>
<cmath>(2, 5, 6)</cmath>
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<cmath>(3, 4, 5)=12</cmath>
<cmath>(3, 4, 6), (3, 5, 7)</cmath>
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<cmath>(2, 3, 4)=9</cmath>
  
The first triple <math>(1, 6, 6)</math> is not scalene, because two of the sides are equal. This leaves <math>\boxed{\textbf{(C)} \quad 3}</math> scalene triangles.
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This leaves <math>\boxed{\textbf{(C)} \quad 3}</math> scalene triangles.
  
 
-coolmath34
 
-coolmath34
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-rubslul
  
 
(If you see any cases I missed out, edit them in.)
 
(If you see any cases I missed out, edit them in.)
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 +
==Video Solution==
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https://youtu.be/LYFaYLiLTXE
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~Lucas
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==See Also==
 
==See Also==
 
{{AHSME 50p box|year=1956|num-b=42|num-a=44}}
 
{{AHSME 50p box|year=1956|num-b=42|num-a=44}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Latest revision as of 17:29, 19 September 2022

Problem 43

The number of scalene triangles having all sides of integral lengths, and perimeter less than $13$ is:

$\textbf{(A)}\ 1 \qquad\textbf{(B)}\ 2 \qquad\textbf{(C)}\ 3 \qquad\textbf{(D)}\ 4 \qquad\textbf{(E)}\ 18$

Solution

We can write all possible triangles adding up to 12 or less \[(2, 4, 5)=11\] \[(3, 4, 5)=12\] \[(2, 3, 4)=9\]

This leaves $\boxed{\textbf{(C)} \quad 3}$ scalene triangles.

-coolmath34

-rubslul

(If you see any cases I missed out, edit them in.)

Video Solution

https://youtu.be/LYFaYLiLTXE

~Lucas

See Also

1956 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 42
Followed by
Problem 44
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All AHSME Problems and Solutions

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