Difference between revisions of "1958 AHSME Problems/Problem 18"
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The area of a circle is doubled when its radius <math> r</math> is increased by <math> n</math>. Then <math> r</math> equals: | The area of a circle is doubled when its radius <math> r</math> is increased by <math> n</math>. Then <math> r</math> equals: | ||
− | <math> \textbf{(A)}\ n(\sqrt{2} | + | <math> \textbf{(A)}\ n(\sqrt{2} + 1)\qquad |
− | \textbf{(B)}\ n(\sqrt{2} | + | \textbf{(B)}\ n(\sqrt{2} - 1)\qquad |
\textbf{(C)}\ n\qquad | \textbf{(C)}\ n\qquad | ||
− | \textbf{(D)}\ n(2 | + | \textbf{(D)}\ n(2 - \sqrt{2})\qquad |
− | \textbf{(E)}\ \frac{n\pi}{\sqrt{2} | + | \textbf{(E)}\ \frac{n\pi}{\sqrt{2} + 1}</math> |
== Solution == | == Solution == |
Revision as of 23:19, 13 March 2015
Problem
The area of a circle is doubled when its radius is increased by . Then equals:
Solution
See Also
1958 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 17 |
Followed by Problem 19 | |
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All AHSME Problems and Solutions |
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