Difference between revisions of "1958 AHSME Problems/Problem 19"
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== Problem == | == Problem == | ||
− | The sides of a right triangle are <math> a</math> and <math> b</math> and the hypotenuse is <math> c</math>. A perpendicular from the vertex divides <math> c</math> into segments <math> r</math> and <math> s</math>, adjacent respectively to <math> a</math> and <math> b</math>. If <math> a : b | + | The sides of a right triangle are <math> a</math> and <math> b</math> and the hypotenuse is <math> c</math>. A perpendicular from the vertex divides <math> c</math> into segments <math> r</math> and <math> s</math>, adjacent respectively to <math> a</math> and <math> b</math>. If <math> a : b = 1 : 3</math>, then the ratio of <math> r</math> to <math> s</math> is: |
<math> \textbf{(A)}\ 1 : 3\qquad | <math> \textbf{(A)}\ 1 : 3\qquad |
Latest revision as of 03:30, 29 June 2017
Problem
The sides of a right triangle are and and the hypotenuse is . A perpendicular from the vertex divides into segments and , adjacent respectively to and . If , then the ratio of to is:
Solution
See Also
1958 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 18 |
Followed by Problem 20 | |
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All AHSME Problems and Solutions |
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