Difference between revisions of "1958 AHSME Problems/Problem 20"

(Created page with "== Problem == If <math> 4^x \minus{} 4^{x \minus{} 1} \equal{} 24</math>, then <math> (2x)^x</math> equals: <math> \textbf{(A)}\ 5\sqrt{5}\qquad \textbf{(B)}\ \sqrt{5}\qquad ...")
 
m (Problem)
 
Line 1: Line 1:
 
== Problem ==
 
== Problem ==
If <math> 4^x \minus{} 4^{x \minus{} 1} \equal{} 24</math>, then <math> (2x)^x</math>  equals:
+
If <math> 4^x - 4^{x - 1} = 24</math>, then <math> (2x)^x</math>  equals:
  
 
<math> \textbf{(A)}\ 5\sqrt{5}\qquad  
 
<math> \textbf{(A)}\ 5\sqrt{5}\qquad  

Latest revision as of 23:19, 13 March 2015

Problem

If $4^x - 4^{x - 1} = 24$, then $(2x)^x$ equals:

$\textbf{(A)}\ 5\sqrt{5}\qquad  \textbf{(B)}\ \sqrt{5}\qquad  \textbf{(C)}\ 25\sqrt{5}\qquad  \textbf{(D)}\ 125\qquad  \textbf{(E)}\ 25$

Solution

$\fbox{}$

See Also

1958 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 19
Followed by
Problem 21
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

Invalid username
Login to AoPS