Difference between revisions of "1958 AHSME Problems/Problem 33"
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== Problem == | == Problem == | ||
| − | For one root of <math> ax^2 | + | For one root of <math> ax^2 + bx + c = 0</math> to be double the other, the coefficients <math> a,\,b,\,c</math> must be related as follows: |
| − | <math> \textbf{(A)}\ 4b^2 | + | <math> \textbf{(A)}\ 4b^2 = 9c\qquad |
| − | \textbf{(B)}\ 2b^2 | + | \textbf{(B)}\ 2b^2 = 9ac\qquad |
| − | \textbf{(C)}\ 2b^2 | + | \textbf{(C)}\ 2b^2 = 9a\qquad \\ |
| − | \textbf{(D)}\ b^2 | + | \textbf{(D)}\ b^2 - 8ac = 0\qquad |
| − | \textbf{(E)}\ 9b^2 | + | \textbf{(E)}\ 9b^2 = 2ac</math> |
== Solution == | == Solution == | ||
Latest revision as of 23:21, 13 March 2015
Problem
For one root of 
to be double the other, the coefficients 
must be related as follows:
Solution
See Also
| 1958 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 32 |
Followed by Problem 34 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
