Difference between revisions of "1958 AHSME Problems/Problem 34"
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== Problem == | == Problem == | ||
− | The numerator of a fraction is <math> 6x | + | The numerator of a fraction is <math> 6x + 1</math>, then denominator is <math> 7 - 4x</math>, and <math> x</math> can have any value between <math> -2</math> and <math> 2</math>, both included. The values of <math> x</math> for which the numerator is greater than the denominator are: |
<math> \textbf{(A)}\ \frac{3}{5} < x \le 2\qquad | <math> \textbf{(A)}\ \frac{3}{5} < x \le 2\qquad | ||
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\textbf{(C)}\ 0 < x \le 2\qquad \\ | \textbf{(C)}\ 0 < x \le 2\qquad \\ | ||
\textbf{(D)}\ 0 \le x \le 2\qquad | \textbf{(D)}\ 0 \le x \le 2\qquad | ||
− | \textbf{(E)}\ | + | \textbf{(E)}\ -2 \le x \le 2</math> |
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== Solution == | == Solution == |
Latest revision as of 23:22, 13 March 2015
Problem
The numerator of a fraction is , then denominator is , and can have any value between and , both included. The values of for which the numerator is greater than the denominator are:
Solution
See Also
1958 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 33 |
Followed by Problem 35 | |
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All AHSME Problems and Solutions |
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