1958 AHSME Problems/Problem 43

Problem

$\overline{AB}$ is the hypotenuse of a right triangle $ABC$ . Median $\overline{AD}$ has length $7$ and median $\overline{BE}$ has length $4$ . The length of $\overline{AB}$ is:

$\textbf{(A)}\ 10\qquad \textbf{(B)}\ 5\sqrt{3}\qquad \textbf{(C)}\ 5\sqrt{2}\qquad \textbf{(D)}\ 2\sqrt{13}\qquad \textbf{(E)}\ 2\sqrt{15}$

Solution

$\fbox{D}$

1958 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 42	Followed by Problem 44
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1958 AHSME Problems/Problem 43

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