Difference between revisions of "1958 AHSME Problems/Problem 49"

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==Problem==
 
==Problem==
  
In the expansion of <math> (a \plus{} b)^n</math> there are <math> n \plus{} 1</math> dissimilar terms. The number of dissimilar terms in the expansion of <math> (a \plus{} b \plus{} c)^{10}</math> is:
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In the expansion of <math> (a + b)^n</math> there are <math> n + 1</math> dissimilar terms. The number of dissimilar terms in the expansion of <math> (a + b + c)^{10}</math> is:
  
 
<math> \textbf{(A)}\ 11\qquad  
 
<math> \textbf{(A)}\ 11\qquad  

Revision as of 08:37, 18 May 2016

Problem

In the expansion of $(a + b)^n$ there are $n + 1$ dissimilar terms. The number of dissimilar terms in the expansion of $(a + b + c)^{10}$ is:

$\textbf{(A)}\ 11\qquad  \textbf{(B)}\ 33\qquad  \textbf{(C)}\ 55\qquad  \textbf{(D)}\ 66\qquad  \textbf{(E)}\ 132$

Solution

Expand the binomial $((a+b)+c)^n$ with the binomial theorem. We have:

\[\sum\limits_{k=0}^{10} \binom{10}{k} (a+b)^k c^{10-k}\]

So for each iteration of the summation operator, we add k+1 dissimilar terms. Therefore our answer is:

\[\sum\limits_{k=0}^{10} k+1 = \frac{11(1+11)}{2} = 66 \to \boxed{\textbf{D}}\]


See also

1958 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 48
Followed by
Problem 50
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All AHSME Problems and Solutions

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