Difference between revisions of "1960 AHSME Problems/Problem 1"
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If <math>2</math> is a solution (root) of <math>x^3+hx+10=0</math>, then <math>h</math> equals: | If <math>2</math> is a solution (root) of <math>x^3+hx+10=0</math>, then <math>h</math> equals: | ||
− | <math>\textbf{(A)}10\qquad \textbf{(B )}9 \qquad \textbf{(C )}2\qquad \textbf{(D )}-2\qquad \textbf{(E )}-9</math> | + | <math>\textbf{(A) }10\qquad \textbf{(B) }9 \qquad \textbf{(C) }2\qquad \textbf{(D) }-2\qquad \textbf{(E) }-9</math> |
==Solution== | ==Solution== | ||
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==See Also== | ==See Also== | ||
− | {{AHSME 40p box|year=1960 |before=[[1959 AHSME]]| | + | {{AHSME 40p box|year=1960|before=[[1959 AHSME]]|num-a=2}} |
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[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] |
Latest revision as of 21:28, 30 December 2020
Problem
If is a solution (root) of , then equals:
Solution
Substitute for . We are given that this equation is true. Solving for gives . The answer is .
See Also
1960 AHSC (Problems • Answer Key • Resources) | ||
Preceded by 1959 AHSME |
Followed by Problem 2 | |
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All AHSME Problems and Solutions |