Difference between revisions of "1960 AHSME Problems/Problem 10"

(Solution)
(Solution)
 
(7 intermediate revisions by 2 users not shown)
Line 21: Line 21:
  
 
==Solution==
 
==Solution==
We can obviously see that statement <math>3</math> contradicts statement <math>6</math> since it says that all men are not good drivers while statement <math>6</math> says they are. So the answer is <math>\boxed{C}</math>
+
<math>\fbox{(C)3}</math>
 +
Because No men are good negates All men are good.

Latest revision as of 13:47, 5 February 2019

Problem 10

Given the following six statements: \[\text{(1) All women are good drivers}\] \[\text{(2) Some women are good drivers}\] \[\text{(3) No men are good drivers}\] \[\text{(4) All men are bad drivers}\] \[\text{(5) At least one man is a bad driver}\] \[\text{(6) All men are good drivers.}\]


The statement that negates statement $(6)$ is:


$\textbf{(A) }(1)\qquad \textbf{(B) }(2)\qquad \textbf{(C) }(3)\qquad \textbf{(D) }(4)\qquad \textbf{(E) }(5)$


Solution

$\fbox{(C)3}$ Because No men are good negates All men are good.

Invalid username
Login to AoPS