Difference between revisions of "1960 AHSME Problems/Problem 36"
Rockmanex3 (talk | contribs) (Solution for Problem 36) |
Rockmanex3 (talk | contribs) m (→Solution) |
||
Line 26: | Line 26: | ||
<cmath>2dn^2</cmath> | <cmath>2dn^2</cmath> | ||
− | The answer is <math>\boxed{\textbf{B}}</math>. | + | The answer is <math>\boxed{\textbf{(B)}}</math>. |
==See Also== | ==See Also== | ||
{{AHSME 40p box|year=1960|num-b=35|num-a=37}} | {{AHSME 40p box|year=1960|num-b=35|num-a=37}} |
Revision as of 00:20, 11 May 2018
Problem 36
Let be the respective sums of terms of the same arithmetic progression with as the first term and as the common difference. Let . Then is dependent on:
Solution
The nth term of the sequence with first term is . That means the sum of the first terms is with first term is .
The 2nth term of the sequence with first term is . That means the sum of the first terms is with first term is .
The 3nth term of the sequence with first term is . That means the sum of the first terms is with first term is .
Substituting , , and with its respective values results in
The answer is .
See Also
1960 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 35 |
Followed by Problem 37 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 | ||
All AHSME Problems and Solutions |