Difference between revisions of "1960 IMO Problems/Problem 3"
m (+ nonexistent template, format, cat) |
(→See also: no header) |
||
| Line 9: | Line 9: | ||
{{solution}} | {{solution}} | ||
| − | |||
{{IMO box|year=1960|num-b=2|num-a=4}} | {{IMO box|year=1960|num-b=2|num-a=4}} | ||
[[Category:Olympiad Geometry Problems]] | [[Category:Olympiad Geometry Problems]] | ||
Revision as of 20:20, 25 October 2007
Problem
In a given right triangle 
, the hypotenuse 
, of length 
, is divided into 
equal parts ( and odd integer). Let 
be the acute angle subtending, from 
, that segment which contains the midpoint of the hypotenuse. Let 
be the length of the altitude to the hypotenuse of the triangle. Prove that:
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
| 1960 IMO (Problems) • Resources | ||
| Preceded by Problem 2 |
1 • 2 • 3 • 4 • 5 • 6 | Followed by Problem 4 |
| All IMO Problems and Solutions | ||
