Difference between revisions of "1961 AHSME Problems/Problem 8"
(Created page with 'Let the two base angles of a triangle be ''A'' and ''B'', with ''B'' larger than ''A''. The altitude to the base divides the vertex angle ''C'' into two parts, <math>C_1 and C_2<…') |
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| − | Let the two base angles of a triangle be ''A'' and ''B'', with ''B'' larger than ''A''. The altitude to the base divides the vertex angle ''C'' into two parts, <math>C_1 and C_2</math>, with <math>C_2</math> adjacent to side ''a''. Then: | + | Let the two base angles of a triangle be ''A'' and ''B'', with ''B'' larger than ''A''. The altitude to the base divides the vertex angle ''C'' into two parts, <math>C_1</math> and <math>C_2</math>, with <math>C_2</math> adjacent to side ''a''. Then: |
(A) <math>C_1+C_2=A+B</math> | (A) <math>C_1+C_2=A+B</math> | ||
Revision as of 17:09, 1 October 2009
Let the two base angles of a triangle be A and B, with B larger than A. The altitude to the base divides the vertex angle C into two parts, 
and 
, with adjacent to side a. Then:
(A) 
(B) 
(C) 
(D) 
(E) 
