Difference between revisions of "1962 AHSME Problems/Problem 1"
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The expression <math>\frac{1^{4y-1}}{5^{-1}+3^{-1}}</math> is equal to: | The expression <math>\frac{1^{4y-1}}{5^{-1}+3^{-1}}</math> is equal to: | ||
<math> \textbf{(A)}\ \frac{4y-1}{8}\qquad\textbf{(B)}\ 8\qquad\textbf{(C)}\ \frac{15}{2}\qquad\textbf{(D)}\ \frac{15}{8}\qquad\textbf{(E)}\ \frac{1}{8} </math> | <math> \textbf{(A)}\ \frac{4y-1}{8}\qquad\textbf{(B)}\ 8\qquad\textbf{(C)}\ \frac{15}{2}\qquad\textbf{(D)}\ \frac{15}{8}\qquad\textbf{(E)}\ \frac{1}{8} </math> | ||
Revision as of 22:20, 9 November 2013
Problem
The expression 
is equal to:
