Difference between revisions of "1962 AHSME Problems/Problem 3"
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| − | + | Let <math>y</math> represent the common difference between the terms. We have <math>(x+1)-y=(x-1)\implies y=2</math>. | |
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| + | Substituting gives us <math>(2x+3)-2=(x+1)\implies 2x+1=x+1\implies x=0</math>. | ||
| + | |||
| + | Therefore, our answer is $\textbf{(B)}\ 0\qquad$ | ||
Revision as of 00:06, 10 November 2013
Problem
The first three terms of an arithmetic progression are 
, in the order shown. The value of 
is:
Solution
Let 
represent the common difference between the terms. We have 
.
Substituting gives us 
.
Therefore, our answer is $\textbf{(B)}\ 0\qquad$
