Difference between revisions of "1963 AHSME Problems/Problem 1"

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==Solution==
 
==Solution==
  
Looking at the domain of the graph, <math>x</math> cannot be <math>-1</math>. Therefore, the answer is <math>\textbf{(D)}</math>
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Looking at the domain of the graph, <math>x</math> cannot be <math>-1</math>. Therefore, the answer is <math>\boxed{\textbf{(D)}}</math>.
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==See Also==
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{{AHSME 40p box|year=1963|before=First Problem|num-a=3}}
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[[Category:Introductory Algebra Problems]]
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{{MAA Notice}}

Revision as of 03:00, 7 June 2018

Problem

Which one of the following points is not on the graph of $y=\dfrac{x}{x+1}$?

$\textbf{(A)}\ (0,0)\qquad \textbf{(B)}\ \left(-\frac{1}{2},-1\right)\qquad \textbf{(C)}\ \left(\frac{1}{2},\frac{1}{3}\right)\qquad \textbf{(D)}\ (-1,1)\qquad \textbf{(E)}\ (-2,2)$

Solution

Looking at the domain of the graph, $x$ cannot be $-1$. Therefore, the answer is $\boxed{\textbf{(D)}}$.

See Also

1963 AHSC (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 3
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All AHSME Problems and Solutions

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