# Difference between revisions of "1964 AHSME Problems/Problem 29"

## Problem

In this figure $\angle RFS=\angle FDR$, $FD=4$ inches, $DR=6$ inches, $FR=5$ inches, $FS=7\dfrac{1}{2}$ inches. The length of $RS$, in inches, is:

$\textbf{(A) }\text{undetermined}\qquad\textbf{(B) }4\qquad\textbf{(C) }5\dfrac{1}{2}\qquad\textbf{(D) }6\qquad\textbf{(E) }6\dfrac{1}{2}\qquad$

$[asy] import olympiad; draw((0,0)--7.5*dir(0)); draw((0,0)--5*dir(55)); draw((0,0)--4*dir(140)); draw(4*dir(140)--5*dir(55)--7.5*dir(0)); markscalefactor=0.1; draw(anglemark((0,0),4*dir(140),5*dir(55))); draw(anglemark(7.5*dir(0),(0,0),5*dir(55))); label("F",(0,0),dir(240)); label("D",4*dir(140),dir(180)); label("R",5*dir(55),dir(80)); label("S",7.5*dir(0),dir(-25)); label("4",2*dir(140),dir(230)); label("5",2.5*dir(55),dir(155)); label("6",(4*dir(140)+5*dir(55))/2,dir(100)); label("7\frac{1}{2}",3.75,dir(-90)); [/asy]$