Difference between revisions of "1964 AHSME Problems/Problem 32"

Revision as of 23:16, 24 July 2019

If $\dfrac{a+b}{b+c}=\dfrac{c+d}{d+a}$ , then:

$\textbf{(A) }a \text{ must equal }c\qquad\textbf{(B) }a+b+c+d\text{ must equal zero}\qquad$

$\textbf{(C) }\text{either }a=c\text{ or }a+b+c+d=0\text{, or both}\qquad$

$\textbf{(D) }a+b+c+d\ne 0\text{ if }a=c\qquad$

$\textbf{(E) }a(b+c+d)=c(a+b+d)$

1964 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 31	Followed by Problem 33
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40
All AHSME Problems and Solutions

@@ Line 10: / Line 10: @@
 <math> \textbf{(E) }a(b+c+d)=c(a+b+d)</math>
+==See Also==
+{{AHSME 40p box|year=1964|num-b=31|num-a=33}}
+[[Category:Introductory Algebra Problems]]
+{{MAA Notice}}