Difference between revisions of "1964 AHSME Problems/Problem 33"

(Created page with "==Problem== <math>P</math> is a point interior to rectangle <math>ABCD</math> and such that <math>PA=3</math> inches, <math>PD=4</math> inches, and <math>PC=5</math> inches. The...")
 
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label("$5$",(4.5,3),dir(120));
 
label("$5$",(4.5,3),dir(120));
 
</asy>
 
</asy>
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==See Also==
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{{AHSME 40p box|year=1964|num-b=32|num-a=34}}
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[[Category:Introductory Geometry Problems]]
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{{MAA Notice}}

Revision as of 23:17, 24 July 2019

Problem

$P$ is a point interior to rectangle $ABCD$ and such that $PA=3$ inches, $PD=4$ inches, and $PC=5$ inches. Then $PB$, in inches, equals:

$\textbf{(A) }2\sqrt{3}\qquad\textbf{(B) }3\sqrt{2}\qquad\textbf{(C) }3\sqrt{3}\qquad\textbf{(D) }4\sqrt{2}\qquad \textbf{(E) }2$

[asy] draw((0,0)--(6.5,0)--(6.5,4.5)--(0,4.5)--cycle); draw((2.5,1.5)--(0,0)); draw((2.5,1.5)--(0,4.5)); draw((2.5,1.5)--(6.5,4.5)); draw((2.5,1.5)--(6.5,0),linetype("8 8")); label("$A$",(0,0),dir(-135)); label("$B$",(6.5,0),dir(-45)); label("$C$",(6.5,4.5),dir(45)); label("$D$",(0,4.5),dir(135)); label("$P$",(2.5,1.5),dir(-90)); label("$3$",(1.25,0.75),dir(120)); label("$4$",(1.25,3),dir(35)); label("$5$",(4.5,3),dir(120)); [/asy]

See Also

1964 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 32
Followed by
Problem 34
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