Difference between revisions of "1964 AHSME Problems/Problem 38"

(Created page with "==Problem== The sides <math>PQ</math> and <math>PR</math> of triangle <math>PQR</math> are respectively of lengths <math>4</math> inches, and <math>7</math> inches. The median <...")
 
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<math>\textbf{(A) }6\qquad\textbf{(B) }7\qquad\textbf{(C) }8\qquad\textbf{(D) }9\qquad \textbf{(E) }10</math>
 
<math>\textbf{(A) }6\qquad\textbf{(B) }7\qquad\textbf{(C) }8\qquad\textbf{(D) }9\qquad \textbf{(E) }10</math>
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==See Also==
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{{AHSME 40p box|year=1964|num-b=37|num-a=39}}
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[[Category:Introductory Algebra Problems]]
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{{MAA Notice}}

Revision as of 23:19, 24 July 2019

Problem

The sides $PQ$ and $PR$ of triangle $PQR$ are respectively of lengths $4$ inches, and $7$ inches. The median $PM$ is $3\frac{1}{2}$ inches. Then $QR$, in inches, is:

$\textbf{(A) }6\qquad\textbf{(B) }7\qquad\textbf{(C) }8\qquad\textbf{(D) }9\qquad \textbf{(E) }10$


See Also

1964 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 37
Followed by
Problem 39
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All AHSME Problems and Solutions

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