Difference between revisions of "1966 AHSME Problems/Problem 37"

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== Solution 2 ==
 
== Solution 2 ==
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Let A,B,G denote the number of hours , respectively.
  
 
== See also ==
 
== See also ==

Revision as of 22:30, 23 December 2019

Problem

Three men, Alpha, Beta, and Gamma, working together, do a job in 6 hours less time than Alpha alone, in 1 hour less time than Beta alone, and in one-half the time needed by Gamma when working alone. Let $h$ be the number of hours needed by Alpha and Beta, working together, to do the job. Then $h$ equals:

$\text{(A) } \frac{5}{2} \quad \text{(B) } \frac{3}{2} \quad \text{(C) } \frac{4}{3} \quad \text{(D) } \frac{5}{4} \quad \text{(E) } \frac{3}{4}$

Solution

$\fbox{C}$

Solution 2

Let A,B,G denote the number of hours , respectively.

See also

1966 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 36
Followed by
Problem 38
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