Difference between revisions of "1967 AHSME Problems/Problem 29"
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== Problem == | == Problem == | ||
− | <math>\overline{AB}</math> is a diameter of a circle. Tangents <math>\overline{AD}</math> and <math>\overline{BC}</math> are drawn so that <math>\overline{AC}</math> and <math>\overline{BD}</math> intersect in a point on the circle. If <math>\overline{AD}=a</math> and <math>\overline{ | + | <math>\overline{AB}</math> is a diameter of a circle. Tangents <math>\overline{AD}</math> and <math>\overline{BC}</math> are drawn so that <math>\overline{AC}</math> and <math>\overline{BD}</math> intersect in a point on the circle. If <math>\overline{AD}=a</math> and <math>\overline{BC}=b</math>, <math>a \not= b</math>, the diameter of the circle is: |
<math>\textbf{(A)}\ |a-b|\qquad | <math>\textbf{(A)}\ |a-b|\qquad |
Latest revision as of 02:56, 23 February 2015
Problem
is a diameter of a circle. Tangents and are drawn so that and intersect in a point on the circle. If and , , the diameter of the circle is:
Solution
See also
1967 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 28 |
Followed by Problem 30 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
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