Difference between revisions of "1967 AHSME Problems/Problem 32"

Revision as of 20:22, 23 June 2015

Problem

In quadrilateral $ABCD$ with diagonals $AC$ and $BD$ , intersecting at $O$ , $BO=4$ , $OD = 6$ , $AO=8$ , $OC=3$ , and $AB=6$ . The length of $AD$ is:

$\textbf{(A)}\ 9\qquad \textbf{(B)}\ 10\qquad \textbf{(C)}\ 6\sqrt{3}\qquad \textbf{(D)}\ 8\sqrt{2}\qquad \textbf{(E)}\ \sqrt{166}$

Solution

$\fbox{E}$

1967 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 31	Followed by Problem 33
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

@@ Line 1: / Line 1: @@
 == Problem ==
-In quadrilateral <math>ABCD</math> with diagonals <math>\overline{AC}</math> and <math>\overline{BD}</math> intersecting at <math>O</math>, <math>\overline{BO}=4</math>, <math>\overline{AO}=8</math>, <math>\overline{OC}=3</math>, and <math>\overline{AB}=6</math>.  The length of <math>\overline{AD}</math> is:
+In quadrilateral <math>ABCD</math> with diagonals <math>AC</math> and <math>BD</math>, intersecting at <math>O</math>, <math>BO=4</math>, <math>OD = 6</math>, <math>AO=8</math>, <math>OC=3</math>, and <math>AB=6</math>.  The length of <math>AD</math> is:
 <math>\textbf{(A)}\ 9\qquad

Page

Toolbox

Search

Difference between revisions of "1967 AHSME Problems/Problem 32"

Revision as of 20:22, 23 June 2015

Problem

Solution

See also