Difference between revisions of "1968 AHSME Problems/Problem 1"

Revision as of 03:26, 29 September 2014

Let $P$ units be the increase in circumference of a circle resulting from an increase in $\pi$ units in the diameter. Then $P$ equals:

$\text{(A) } \frac{1}{\pi}\quad\text{(B) } \pi\quad\text{(C) } \frac{\pi^2}{2}\quad\text{(D) } \pi^2\quad\text{(E) } 2\pi$

$\fbox{D}$

1968 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 1	Followed by Problem 2
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30
All AHSME Problems and Solutions

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 {{AHSME box|year=1968|num-b=1|num-a=2}}
-[[Category: Introductory Algebra Problems]]
+[[Category: Introductory Geometry Problems]]
 {{MAA Notice}}