Difference between revisions of "1968 AHSME Problems/Problem 12"

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== Solution ==
 
== Solution ==
<math>\fbox{}</math>
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<math>\fbox{C}</math>
  
 
== See also ==
 
== See also ==

Revision as of 02:30, 29 September 2014

Problem

A circle passes through the vertices of a triangle with side-lengths $7\tfrac{1}{2},10,12\tfrac{1}{2}.$ The radius of the circle is:

$\text{(A) } \frac{15}{4}\quad \text{(B) } 5\quad \text{(C) } \frac{25}{4}\quad \text{(D) } \frac{35}{4}\quad \text{(E) } \frac{15\sqrt{2}}{2}$

Solution

$\fbox{C}$

See also

1968 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 11
Followed by
Problem 13
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

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