Difference between revisions of "1969 AHSME Problems/Problem 1"
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== Problem == | == Problem == | ||
− | When <math>x</math> is added to both the numerator and | + | When <math>x</math> is added to both the numerator and denominator of the fraction |
+ | <math>\frac{a}{b},a \ne b,b \ne 0</math>, the value of the fraction is changed to <math>\frac{c}{d}</math>. | ||
+ | Then <math>x</math> equals: | ||
<math>\text{(A) } \frac{1}{c-d}\quad | <math>\text{(A) } \frac{1}{c-d}\quad |
Revision as of 15:50, 30 September 2014
Problem
When is added to both the numerator and denominator of the fraction , the value of the fraction is changed to . Then equals:
Solution
See also
1969 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.