1970 AHSME Problems/Problem 34

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Problem

The greatest integer that will divide $13511$, $13903$ and $14589$ and leave the same remainder is

$\text{(A) } 28\quad \text{(B) } 49\quad \text{(C) } 98\quad\\ \text{(D) an odd multiple of } 7 \text{ greater than } 49\quad\\ \text{(E) an even multiple of } 7 \text{ greater than } 98$

Solution

$\fbox{C}$

See also

1970 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 33
Followed by
Problem 35
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