1971 AHSME Problems/Problem 10
Revision as of 19:19, 28 January 2021 by Coolmath34 (talk | contribs) (Created page with "== Problem == Each of a group of <math>50</math> girls is blonde or brunette and is blue eyed of brown eyed. If <math>14</math> are blue-eyed blondes, <math>31</math> are br...")
Problem
Each of a group of 
girls is blonde or brunette and is blue eyed of brown eyed. If 
are blue-eyed blondes,
are brunettes, and 
are brown-eyed, then the number of brown-eyed brunettes is
Solution
There are brunettes, so there are 
blondes. We know there are blue-eyed blondes, so there are 
brown-eyed blondes.
Next, we know that people are brown-eyed, so there are 
brown-eyed brunettes.
The answer is 
-edited by coolmath34
