Difference between revisions of "1971 Canadian MO Problems/Problem 1"
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== Solution == | == Solution == | ||
First, extend <math>CO</math> to meet the circle at <math>P.</math> Let the radius be <math>r.</math> Applying [[power of a point]], | First, extend <math>CO</math> to meet the circle at <math>P.</math> Let the radius be <math>r.</math> Applying [[power of a point]], | ||
− | <math>( | + | <math>(EP)(CE)=(BE)(ED)</math> and <math>2r-1=15.</math> Hence, <math>r=8.</math> |
== See Also == | == See Also == |
Revision as of 23:49, 7 November 2018
Problem
is a chord of a circle such that and Let be the center of the circle. Join and extend to cut the circle at Given find the radius of the circle
Solution
First, extend to meet the circle at Let the radius be Applying power of a point, and Hence,
See Also
1971 Canadian MO (Problems) | ||
Preceded by First Question |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • | Followed by Problem 2 |