Difference between revisions of "1973 AHSME Problems/Problem 23"

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There are three red faces, and two are on the card that is completely red, so our answer is <math>\frac{2}{3}</math>
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There are three red faces, and two are on the card that is completely red, so our answer is <math>\frac{2}{3}</math>.

Revision as of 20:55, 21 February 2015

There are three red faces, and two are on the card that is completely red, so our answer is $\frac{2}{3}$.