# 1975 AHSME Problems/Problem 14

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## Problem 14

If the $whatsis$ is $so$ when the $whosis$ is $is$ and the $so$ and $so$ is $is \cdot so$, what is the $whosis \cdot whatsis$ when the $whosis$ is $so$, the $so$ and $so$ is $so \cdot so$ and the $is$ is two ($whatsis, whosis, is$ and $so$ are variables taking positive values)?

$\textbf{(A)}\ whosis \cdot is \cdot so \qquad \textbf{(B)}\ whosis \qquad \textbf{(C)}\ is \qquad \textbf{(D)}\ so\qquad \textbf{(E)}\ so\text{ and }so$

## Solution

From the problem, we are given:

$whatsis = so$
$whosis = is$
$so + so = is \cdot so$

We want to find what $whatsis \cdot whosis$ is when $whosis = so$, $so + so = so \cdot so$, and $is = 2$.

Since $is = 2$ and $so + so = is \cdot so = so \cdot so$ (from the given), that means $so = 2$. Now we know that $whatsis = 2$ and $whosis = 2$ as well because they are equal to $so$ and $is$, respectively.

Plugging in the values, we get $whatsis \cdot whosis = so \cdot is = 4$. This also means that $whatsis \cdot whosis = so + so$.

Taking a look at the answer choices, we see that our answer is $\boxed{\textbf{(E)}\ so\text{ and }so}$. ~jiang147369

## See Also

 1975 AHSME (Problems • Answer Key • Resources) Preceded byProblem 13 Followed byProblem 15 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 All AHSME Problems and Solutions

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