Difference between revisions of "1975 AHSME Problems/Problem 16"

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\textbf{(E)}\ \frac{9}{2} \qquad
 
\textbf{(E)}\ \frac{9}{2} \qquad
 
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==Solution==
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nothing yet :(
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==See Also==
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{{AHSME box|year=1975|num-b=15|num-a=17}}
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{{MAA Notice}}

Latest revision as of 16:17, 19 January 2021

Problem

If the first term of an infinite geometric series is a positive integer, the common ratio is the reciprocal of a positive integer, and the sum of the series is $3$, then the sum of the first two terms of the series is

$\textbf{(A)}\ \frac{1}{3} \qquad \textbf{(B)}\ \frac{2}{3} \qquad \textbf{(C)}\ \frac{8}{3} \qquad \textbf{(D)}\ 2           \qquad \textbf{(E)}\ \frac{9}{2} \qquad$

Solution

nothing yet :(

See Also

1975 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 15
Followed by
Problem 17
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