# Difference between revisions of "1975 AHSME Problems/Problem 22"

(Created page with "Since the roots are both positive integers, we can say that <math>x^2-px+q=(x-1)(x-q)</math> since <math>q</math> only has <math>2</math> divisors. Thus, the roots are <math>1...") |
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<math>IV</math> is true because <math>2+3=5</math> is prime. | <math>IV</math> is true because <math>2+3=5</math> is prime. | ||

Thus, the answer is <math>\textbf{(E)}</math>. | Thus, the answer is <math>\textbf{(E)}</math>. | ||

+ | -brainiacmaniac31 |

## Revision as of 23:38, 6 January 2020

Since the roots are both positive integers, we can say that since only has divisors. Thus, the roots are and and . The only two primes which differ by are so and . is true because . is true because one of the roots is which is prime. is true because is prime. is true because is prime. Thus, the answer is . -brainiacmaniac31