Difference between revisions of "1976 AHSME Problems/Problem 3"
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The lengths to the side are <math>1, \sqrt{2^2+1^2}, \sqrt{2^2+1^2}, 1</math>, respectively. Therefore, the sum is <math>2+2\sqrt{5}\Rightarrow \textbf{(E)}</math>.~MathJams | The lengths to the side are <math>1, \sqrt{2^2+1^2}, \sqrt{2^2+1^2}, 1</math>, respectively. Therefore, the sum is <math>2+2\sqrt{5}\Rightarrow \textbf{(E)}</math>.~MathJams | ||
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Revision as of 20:03, 12 July 2020
Problem 3
The sum of the distances from one vertex of a square with sides of length 
to the midpoints of each of the sides of the square is
Solution
The lengths to the side are 
, respectively. Therefore, the sum is 
.~MathJams
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