1977 AHSME Problems/Problem 15

Revision as of 13:31, 21 November 2016 by E power pi times i (talk | contribs) (Created page with "== Problem 15 == <asy> size(120); real t = 2/sqrt(3); real x = 1 + sqrt(3); pair A = t*dir(90), D = x*A; pair B = t*dir(210), E = x*B; pair C = t*dir(330), F = x*C; draw(D--E...")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Problem 15

[asy] size(120); real t = 2/sqrt(3); real x = 1 + sqrt(3); pair A = t*dir(90), D = x*A; pair B = t*dir(210), E = x*B; pair C = t*dir(330), F = x*C; draw(D--E--F--cycle); draw(Circle(A, 1)); draw(Circle(B, 1)); draw(Circle(C, 1)); //Credit to MSTang for the diagram [/asy]

Each of the three circles in the adjoining figure is externally tangent to the other two, and each side of the triangle is tangent to two of the circles. If each circle has radius three, then the perimeter of the triangle is

$\textbf{(A) }36+9\sqrt{2}\qquad \textbf{(B) }36+6\sqrt{3}\qquad \textbf{(C) }36+9\sqrt{3}\qquad \textbf{(D) }18+18\sqrt{3}\qquad \textbf{(E) }45$

Solution

Solution by e_power_pi_times_i

Draw perpendicular lines from the radii to the circles to the sides of the triangle, and lines from the radii of the circles to the vertices of the triangle. Because