# Difference between revisions of "1979 AHSME Problems/Problem 2"

(Created page with "==Solution== Moving all variables to one side of the equation, we can use Simon's Favorite Factoring Trick to factor the equation into <cmath>(x+1)(y-1) = -1</cmath> Plugging...") |
(→Solution) |
||

Line 1: | Line 1: | ||

==Solution== | ==Solution== | ||

− | Moving all variables to one side of the equation, we can use Simon's Favorite Factoring Trick to factor the equation into <cmath>(x+1)(y-1) = -1</cmath> Plugging in <math>-1</math> and <math>1</math> as the <math>x</math> and <math>y</math> sides respectively, we get <math>x = -2</math> and <math>y = 2</math>. Plugging this in to <math>1 | + | Moving all variables to one side of the equation, we can use Simon's Favorite Factoring Trick to factor the equation into <cmath>(x+1)(y-1) = -1</cmath> Plugging in <math>-1</math> and <math>1</math> as the <math>x</math> and <math>y</math> sides respectively, we get <math>x = -2</math> and <math>y = 2</math>. Plugging this in to <math>\frac{1}{x}-\frac{1}{y}</math> gives us <math>\boxed{-1}</math> as our final answer. |

## Revision as of 15:01, 6 July 2016

## Solution

Moving all variables to one side of the equation, we can use Simon's Favorite Factoring Trick to factor the equation into Plugging in and as the and sides respectively, we get and . Plugging this in to gives us as our final answer.