https://artofproblemsolving.com/wiki/index.php?title=1981_AHSME_Problems/Problem_9&feed=atom&action=history1981 AHSME Problems/Problem 9 - Revision history2024-03-28T11:42:21ZRevision history for this page on the wikiMediaWiki 1.31.1https://artofproblemsolving.com/wiki/index.php?title=1981_AHSME_Problems/Problem_9&diff=93202&oldid=prevCoolmath34: Created page with "Because the space diagonal of a cube with side length <math>s</math> is <math>s \sqrt{3},</math> the side length of the cube in this problem is <math>\frac{a}{\sqrt{3}}.</math..."2018-03-13T01:14:00Z<p>Created page with "Because the space diagonal of a cube with side length <math>s</math> is <math>s \sqrt{3},</math> the side length of the cube in this problem is <math>\frac{a}{\sqrt{3}}.</math..."</p>
<p><b>New page</b></p><div>Because the space diagonal of a cube with side length <math>s</math> is <math>s \sqrt{3},</math> the side length of the cube in this problem is <math>\frac{a}{\sqrt{3}}.</math> The surface area of the cube is therefore <math>6(\frac{a}{\sqrt{3}})^2=6 \cdot \frac{a^2}{3}=\boxed{2a^2},</math> which is answer choice <math>\boxed{\text{A}}.</math></div>Coolmath34