Difference between revisions of "1982 AHSME Problems/Problem 1"
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| − | + | ==Problem== | |
| − | Thus | + | |
| + | When the polynomial <math>x^3-2</math> is divided by the polynomial <math>x^2-2</math>, the remainder is | ||
| + | |||
| + | <math>\text{(A)} \ 2 \qquad | ||
| + | \text{(B)} \ -2 \qquad | ||
| + | \text{(C)} \ -2x-2 \qquad | ||
| + | \text{(D)} \ 2x+2 \qquad | ||
| + | \text{(E)} \ 2x-2</math> | ||
| + | |||
| + | ==Solution== | ||
| + | |||
| + | Working out <math>\frac{x^3-2}{x^2-2}</math> using polynomial long division, we get <math>x + \frac{2x-2}{x^2-2}</math>. | ||
| + | Thus the answer is <math>2x -2</math>, for choice <math>\boxed{(E)}</math>. | ||
| + | |||
| + | ==See Also== | ||
| + | {{AHSME box|year=1982|before=First Question|num-a=2}} | ||
| + | |||
| + | {{MAA Notice}} | ||
Revision as of 00:01, 21 February 2019
Problem
When the polynomial 
is divided by the polynomial 
, the remainder is
Solution
Working out 
using polynomial long division, we get 
.
Thus the answer is 
, for choice 
.
See Also
| 1982 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
