1982 AHSME Problems/Problem 15
Let denote the greatest integer not exceeding . Let and satisfy the simultaneous equations
If is not an integer, then is
We simply ignore the floor of . Then, we have = = . Solving for , we get . For the floor of , we have is between and . Plugging in + = for , we have . We have =
Solution 2 (RIGID)
Since is not an integer, we let , where .
So . .
. . So we know that is between 4 and 5. . So is between and . Select .