Difference between revisions of "1982 AHSME Problems/Problem 2"
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| − | + | ==Problem== | |
| − | <math> | + | If a number eight times as large as <math>x</math> is increased by two, then one fourth of the result equals |
| − | + | <math>\text{(A)} \ 2x + \frac{1}{2} \qquad | |
| + | \text{(B)} \ x + \frac{1}{2} \qquad | ||
| + | \text{(C)} \ 2x+2 \qquad | ||
| + | \text{(D)}\ 2x+4 \qquad | ||
| + | \text{(E)}\ 2x+16 </math> | ||
| + | |||
| + | ==Solution== | ||
| + | |||
| + | The number <math>8</math> times as large as <math>x</math> will be <math>8x</math>, and <math>8x</math> increased by two will give <math>8x+2</math>. Hence finally, the answer is <math>\frac{1}{4}(8x+2) = \boxed{\text{(A)}\ 2x + \frac{1}{2}}</math>. | ||
| + | |||
| + | ==See Also== | ||
| + | {{AHSME box|year=1982|num-b=1|num-a=3}} | ||
| + | |||
| + | {{MAA Notice}} | ||
Latest revision as of 00:04, 21 February 2019
Problem
If a number eight times as large as 
is increased by two, then one fourth of the result equals
Solution
The number 
times as large as will be 
, and increased by two will give 
. Hence finally, the answer is 
.
See Also
| 1982 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
